What is the quotient when [tex]-12x^9 + 3x^7 + 24x^6[/tex] is divided by [tex]6x[/tex]?

A. [tex]-2x^8 + \frac{1}{2}x^6 + 4x^5[/tex]
B. [tex]2x^9 + 2x^7 + 4x^6[/tex]
C. [tex]-2x^8 + 2x^6 + 4x^5[/tex]
D. [tex]2x^8 + \frac{1}{2}x^6 + 4x^5[/tex]

To find the quotient when -12x9+3x7+24x6 is divided by 6x, we can individually divide each term in the polynomial by 6x. Firstly, -12x⁹ divided by 6x is -2x⁸, using the rule of division for exponents where you subtract the exponents (in this case 9-1=8) which leads to the term of x to the power 8, and the division -12 by 6 which equals to -2.

Secondly, 3x⁷ divided by 6x equals 0.5x⁶. Similarly, we subtract the exponents (7-1=6), and divide the coefficients, 3 by 6, which provides 0.5. Lastly, 24x⁶ divided by 6x will result in 4x⁵.

So overall, -12x9+3x7+24x6 divided by 6x equals -2x⁸+ 0.5x⁶+4x⁵ which matches answer D exactly.

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What is the quotient when [tex]-12x^9 + 3x^7 + 24x^6[/tex] is divided by [tex]6x[/tex]?A. [tex]-2x^8 + \frac{1}{2}x^6 + 4x^5[/tex] B. [tex]2x^9 + 2x^7 + 4x^6[/tex] C. [tex]-2x^8 + 2x^6 + 4x^5[/tex] D. [tex]2x^8 + \frac{1}{2}x^6 + 4x^5[/tex]

Answer :

Final answer:

Explanation:

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Other Questions

What is the quotient when [tex]-12x^9 + 3x^7 + 24x^6[/tex] is divided by [tex]6x[/tex]?

A. [tex]-2x^8 + \frac{1}{2}x^6 + 4x^5[/tex]
B. [tex]2x^9 + 2x^7 + 4x^6[/tex]
C. [tex]-2x^8 + 2x^6 + 4x^5[/tex]
D. [tex]2x^8 + \frac{1}{2}x^6 + 4x^5[/tex]