Answer :
The acceleration of the fireman sliding down a pole who weighs 100 kg with a frictional force of 137 N is 8.44 m / s²
According to Newton's second law of motion
F = m a
Net downwards force = F - f
F = Applied force
f = Frictional force
m = Mass
a = Acceleration
m = 100 kg
f = 137 N
g = 9.81 m / s²
F = m g
F = 100 * 9.81
F = 981 N
Net downwards force = 981 - 137
Net downwards force = 844 N
F = m a
a = 844 / 100
a = 8.44 m / s²
Therefore, the acceleration of the fireman is 8.44 m / s²
To know more about Newton's second law of motion
https://brainly.com/question/13447525
#SPJ1
