Answer :
To find the quotient of the division problem [tex]\( 7069 \div 328 \)[/tex], you can approach it step-by-step using traditional long division:
1. Divide: First, see how many times 328 fits into the first part of 7069. 328 fits into 706 exactly 2 times because [tex]\( 328 \times 2 = 656 \)[/tex].
2. Subtract: Subtract 656 from 706 to find the remainder. This gives [tex]\( 706 - 656 = 50 \)[/tex].
3. Bring down the next digit: Bring down the next digit (9) from 7069 to get 509.
4. Repeat the division: Now, determine how many times 328 fits into 509. 328 fits into 509 1 time because [tex]\( 328 \times 1 = 328 \)[/tex].
5. Subtract: Subtract 328 from 509 to find the remainder. This gives [tex]\( 509 - 328 = 181 \)[/tex].
Putting it all together, the quotient is 21 with a remainder of 181. Therefore, the answer is:
D. 21 r 181
1. Divide: First, see how many times 328 fits into the first part of 7069. 328 fits into 706 exactly 2 times because [tex]\( 328 \times 2 = 656 \)[/tex].
2. Subtract: Subtract 656 from 706 to find the remainder. This gives [tex]\( 706 - 656 = 50 \)[/tex].
3. Bring down the next digit: Bring down the next digit (9) from 7069 to get 509.
4. Repeat the division: Now, determine how many times 328 fits into 509. 328 fits into 509 1 time because [tex]\( 328 \times 1 = 328 \)[/tex].
5. Subtract: Subtract 328 from 509 to find the remainder. This gives [tex]\( 509 - 328 = 181 \)[/tex].
Putting it all together, the quotient is 21 with a remainder of 181. Therefore, the answer is:
D. 21 r 181
