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------------------------------------------------ What is the quotient of the following division problem?

[tex]\[ 16 \longdiv {1518} \][/tex]

A. 94 r 13
B. 96 r 11
C. 94 r 14
D. 93 r 12

Sure! Let's solve the division problem step by step.

We are given the division problem:
[tex]\[ 16 \longdiv { 1518 } \][/tex]

1. Set up the division:
[tex]\[
\require{enclose}
16 \enclose{longdiv}{1518}
\][/tex]

2. Divide the first part (the first two numbers):
- 16 goes into 15 zero times. So we move to the first three digits.

Now consider 151:
- 16 goes into 151 nine times because [tex]\(16 \times 9 = 144\)[/tex].

3. Multiply and subtract:
- Multiply 16 by 9 to get 144.
- Subtract 144 from 151 to get 7.
[tex]\[
\require{enclose}
16 \enclose{longdiv}{1518} \newline
- 144 \newline
\underline{\ 7 8}
\][/tex]

4. Bring down the next digit (8):
- Now we have 78.
- 16 goes into 78 four times because [tex]\( 16 \times 4 = 64 \)[/tex].

5. Multiply and subtract again:
- Multiply 16 by 4 to get 64.
- Subtract 64 from 78 to get 14.
[tex]\[
\require{enclose}
16 \enclose{longdiv}{1518} \newline
- 144 \newline
\underline{\ 7 8} \newline
- 64 \newline
\underline{\ 14}
\][/tex]

6. Result:
- The quotient is 94 and the remainder is 14.

So, the quotient of the division problem [tex]\(16 \longdiv { 1518 }\)[/tex] is:
[tex]\[ \boxed {94 \text { r } 14} \][/tex]

The correct answer is:
C. 94 r 14