High School

What is the pressure inside a 39.5 L container holding 100.5 kg of argon gas at 21.0 °C?

Answer :

The pressure inside the container is 156113.8 kPa.

The pressure inside the container can be calculated using the Ideal Gas Law equation:

PV = nRT,

where P is pressure, V is volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.
First, we need to convert the given values to the appropriate units:

Volume (V) = 39.5 L
Mass (m) = 100.5 kg = 100500 g
Temperature (T) = 21.0°C = 294.15 K
Next, we need to calculate the number of moles (n) of argon gas using the molar mass of argon (39.948 g/mol):
n = m / M

n = 100500 g / 39.948 g/mol

n = 2516.4 mol
Now we can plug in the values into the Ideal Gas Law equation and solve for pressure (P):

P = (nRT) / V

P = (2516.4 mol)(8.3145 L·kPa/(mol·K))(294.15 K) / 39.5 L

P = 156113.8 kPa

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