Answer :
Final answer:
In order to prepare 1.00 L of a 0.646 M HCl solution from a 2.00 M HCl solution, one needs to dilute 0.323 L of the 2.00 M HCl solution with distilled water until the total volume of the solution is 1.00 L.
Explanation:
To prepare 1.00 L of a 0.646 M HCl solution using a 2.00 M HCl solution, you will need to use the formula of molarity which is M1V1=M2V2. In this case, M1 is the initial molarity (2.00 M), V1 is the volume of the initial solution you need to figure out, M2 is the final molarity (0.646 M), and V2 is the final volume (1.00 L).
Re-arranging the terms, V1 = M2V2 / M1 = 0.646 L * 1.00 L / 2.00 M = 0.323 L. This indicates that you will need to take 0.323 L (or 323 mL) of the 2.00 M HCl solution and dilute it with distilled water until the total volume of the solution is 1.00 L.
Therefore, the correct answer is A. Dilute 0.323 L of 2.00 M HCl solution with distilled water to a total volume of 1.00 L.
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