Answer :
To find the potential energy of a bicycle at the top of a hill, we can use the formula for gravitational potential energy, which is:
[tex]\[ PE = m \times g \times h \][/tex]
where:
- [tex]\( PE \)[/tex] is the potential energy,
- [tex]\( m \)[/tex] is the mass of the object (in kilograms),
- [tex]\( g \)[/tex] is the acceleration due to gravity (approximately [tex]\( 9.8 \, \text{m/s}^2 \)[/tex] on Earth),
- [tex]\( h \)[/tex] is the height above the ground (in meters).
Now, let's plug in the values given in the problem:
- The mass [tex]\( m \)[/tex] of the bicycle is [tex]\( 25 \, \text{kg} \)[/tex],
- The acceleration due to gravity [tex]\( g \)[/tex] is [tex]\( 9.8 \, \text{m/s}^2 \)[/tex],
- The height [tex]\( h \)[/tex] of the hill is [tex]\( 3 \, \text{m} \)[/tex].
Substitute the values into the formula:
[tex]\[ PE = 25 \, \text{kg} \times 9.8 \, \text{m/s}^2 \times 3 \, \text{m} \][/tex]
[tex]\[ PE = 735 \, \text{J} \][/tex]
Therefore, the potential energy of the bicycle at the top of the hill is [tex]\( 735 \, \text{J} \)[/tex].
So, the correct answer is 735 J.
[tex]\[ PE = m \times g \times h \][/tex]
where:
- [tex]\( PE \)[/tex] is the potential energy,
- [tex]\( m \)[/tex] is the mass of the object (in kilograms),
- [tex]\( g \)[/tex] is the acceleration due to gravity (approximately [tex]\( 9.8 \, \text{m/s}^2 \)[/tex] on Earth),
- [tex]\( h \)[/tex] is the height above the ground (in meters).
Now, let's plug in the values given in the problem:
- The mass [tex]\( m \)[/tex] of the bicycle is [tex]\( 25 \, \text{kg} \)[/tex],
- The acceleration due to gravity [tex]\( g \)[/tex] is [tex]\( 9.8 \, \text{m/s}^2 \)[/tex],
- The height [tex]\( h \)[/tex] of the hill is [tex]\( 3 \, \text{m} \)[/tex].
Substitute the values into the formula:
[tex]\[ PE = 25 \, \text{kg} \times 9.8 \, \text{m/s}^2 \times 3 \, \text{m} \][/tex]
[tex]\[ PE = 735 \, \text{J} \][/tex]
Therefore, the potential energy of the bicycle at the top of the hill is [tex]\( 735 \, \text{J} \)[/tex].
So, the correct answer is 735 J.
