Answer :
Final answer:
If 8-year-old George had the proficiency of an average 10-year-old on the Stanford-Binet test, his IQ would be 125. This score indicates superior intelligence, as it exceeds the average IQ score of 100.
Explanation:
If 8-year-old George had responded to the original Stanford-Binet with the proficiency of an average 10-year-old, he would be said to have an IQ of 125. This is calculated using the formula for IQ: (Mental Age / Chronological Age) × 100 = IQ. Therefore, his IQ would be (10 / 8) × 100 = 125.
In this context, an IQ score of 100 is average, meaning a person's mental age matches their chronological age. The Stanford-Binet test has become a widely recognized tool for assessing intelligence and cognitive abilities. A score of 125 indicates that George is performing at a level higher than his peers, as it is higher than the average IQ score of 100. A child with an IQ of 125 is considered to have superior intelligence according to the IQ score range provided by the test.
