Answer :
To find the potential energy of a 25 kg bicycle resting at the top of a 3-meter-high hill, we use the formula for potential energy:
[tex]\[ PE = m \times g \times h \][/tex]
Here,
- [tex]\( m \)[/tex] is the mass of the bicycle, which is 25 kg,
- [tex]\( g \)[/tex] is the acceleration due to gravity, which is approximately 9.8 m/s²,
- [tex]\( h \)[/tex] is the height of the hill, which is 3 m.
Let's plug in these values:
[tex]\[ PE = 25 \, \text{kg} \times 9.8 \, \text{m/s}^2 \times 3 \, \text{m} \][/tex]
[tex]\[ PE = 25 \times 9.8 \times 3 \][/tex]
[tex]\[ PE = 735 \, \text{Joules} \][/tex]
So the potential energy of the bicycle at the top of the hill is 735 J.
[tex]\[ PE = m \times g \times h \][/tex]
Here,
- [tex]\( m \)[/tex] is the mass of the bicycle, which is 25 kg,
- [tex]\( g \)[/tex] is the acceleration due to gravity, which is approximately 9.8 m/s²,
- [tex]\( h \)[/tex] is the height of the hill, which is 3 m.
Let's plug in these values:
[tex]\[ PE = 25 \, \text{kg} \times 9.8 \, \text{m/s}^2 \times 3 \, \text{m} \][/tex]
[tex]\[ PE = 25 \times 9.8 \times 3 \][/tex]
[tex]\[ PE = 735 \, \text{Joules} \][/tex]
So the potential energy of the bicycle at the top of the hill is 735 J.
