Answer :
To determine the potential energy of the bicycle at the top of the hill, you can use the formula for gravitational potential energy:
[tex]\[ PE = m \times g \times h \][/tex]
where:
- [tex]\( PE \)[/tex] is the potential energy,
- [tex]\( m \)[/tex] is the mass of the object (in kilograms),
- [tex]\( g \)[/tex] is the acceleration due to gravity (approximately [tex]\( 9.8 \, \text{m/s}^2 \)[/tex]),
- [tex]\( h \)[/tex] is the height above the ground (in meters).
Given:
- The mass of the bicycle [tex]\( m = 25 \, \text{kg} \)[/tex]
- The height of the hill [tex]\( h = 3 \, \text{meters} \)[/tex]
- The gravitational acceleration [tex]\( g = 9.8 \, \text{m/s}^2 \)[/tex]
Substitute these values into the formula:
[tex]\[ PE = 25 \times 9.8 \times 3 \][/tex]
Calculate step by step:
1. First, multiply the mass and gravity:
[tex]\[ 25 \times 9.8 = 245 \][/tex]
2. Next, multiply the result by the height:
[tex]\[ 245 \times 3 = 735 \][/tex]
Therefore, the potential energy of the bicycle at the top of the hill is 735 Joules. The correct answer is 735 J.
[tex]\[ PE = m \times g \times h \][/tex]
where:
- [tex]\( PE \)[/tex] is the potential energy,
- [tex]\( m \)[/tex] is the mass of the object (in kilograms),
- [tex]\( g \)[/tex] is the acceleration due to gravity (approximately [tex]\( 9.8 \, \text{m/s}^2 \)[/tex]),
- [tex]\( h \)[/tex] is the height above the ground (in meters).
Given:
- The mass of the bicycle [tex]\( m = 25 \, \text{kg} \)[/tex]
- The height of the hill [tex]\( h = 3 \, \text{meters} \)[/tex]
- The gravitational acceleration [tex]\( g = 9.8 \, \text{m/s}^2 \)[/tex]
Substitute these values into the formula:
[tex]\[ PE = 25 \times 9.8 \times 3 \][/tex]
Calculate step by step:
1. First, multiply the mass and gravity:
[tex]\[ 25 \times 9.8 = 245 \][/tex]
2. Next, multiply the result by the height:
[tex]\[ 245 \times 3 = 735 \][/tex]
Therefore, the potential energy of the bicycle at the top of the hill is 735 Joules. The correct answer is 735 J.
