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------------------------------------------------ What is the potential energy of a 25 kg bicycle resting at the top of a hill 3 m high?

(Formula: [tex]PE = mgh[/tex])

A. 75 J
B. 735 J
C. 245 J
D. 37.8 J

Answer :

To find the potential energy of a 25 kg bicycle resting at the top of a hill 3 meters high, we can use the formula for gravitational potential energy, which is:

[tex]\[ PE = m \cdot g \cdot h \][/tex]

where:
- [tex]\( PE \)[/tex] is the potential energy,
- [tex]\( m \)[/tex] is the mass of the object (in kilograms),
- [tex]\( g \)[/tex] is the acceleration due to gravity (approximately [tex]\( 9.8 \, \text{m/s}^2 \)[/tex]),
- [tex]\( h \)[/tex] is the height (in meters).

Given:
- The mass [tex]\( m = 25 \, \text{kg} \)[/tex],
- The gravitational acceleration [tex]\( g = 9.8 \, \text{m/s}^2 \)[/tex],
- The height [tex]\( h = 3 \, \text{m} \)[/tex].

Substitute these values into the formula:

[tex]\[ PE = 25 \, \text{kg} \times 9.8 \, \text{m/s}^2 \times 3 \, \text{m} \][/tex]

Multiplying these together:

[tex]\[ PE = 25 \times 9.8 \times 3 \][/tex]

[tex]\[ PE = 735 \, \text{J} \][/tex]

Therefore, the potential energy of the bicycle is 735 J.