Answer :
To find the potential energy of a 25 kg bicycle resting at the top of a hill 3 meters high, we can use the formula for gravitational potential energy:
[tex]\[ \text{Potential Energy} (PE) = m \cdot g \cdot h \][/tex]
where:
- [tex]\( m \)[/tex] is the mass of the object, which is 25 kg,
- [tex]\( g \)[/tex] is the acceleration due to gravity, which is approximately 9.8 m/s²,
- [tex]\( h \)[/tex] is the height, which is 3 meters.
Now, let's substitute these values into the formula:
[tex]\[ PE = 25 \, \text{kg} \times 9.8 \, \text{m/s}^2 \times 3 \, \text{m} \][/tex]
[tex]\[ PE = 735 \, \text{Joules} \][/tex]
Therefore, the potential energy of the bicycle is 735 Joules. This corresponds to the second choice in the options provided:
735 J
[tex]\[ \text{Potential Energy} (PE) = m \cdot g \cdot h \][/tex]
where:
- [tex]\( m \)[/tex] is the mass of the object, which is 25 kg,
- [tex]\( g \)[/tex] is the acceleration due to gravity, which is approximately 9.8 m/s²,
- [tex]\( h \)[/tex] is the height, which is 3 meters.
Now, let's substitute these values into the formula:
[tex]\[ PE = 25 \, \text{kg} \times 9.8 \, \text{m/s}^2 \times 3 \, \text{m} \][/tex]
[tex]\[ PE = 735 \, \text{Joules} \][/tex]
Therefore, the potential energy of the bicycle is 735 Joules. This corresponds to the second choice in the options provided:
735 J
