Answer :
To find the molarity of the solution, we first determine the number of moles of lithium chloride ([tex]$\mathrm{LiCl}$[/tex]) and then divide by the volume of the solution in liters.
Step 1: Calculate the Moles
Given:
- Mass of [tex]$\mathrm{LiCl}$[/tex]: [tex]$39.4 \text{ g}$[/tex]
- Molar mass of [tex]$\mathrm{LiCl}$[/tex]: [tex]$42.39 \text{ g/mol}$[/tex]
The number of moles is calculated using the formula:
[tex]$$
\text{moles} = \frac{\text{mass}}{\text{molar mass}} = \frac{39.4 \text{ g}}{42.39 \text{ g/mol}}
$$[/tex]
This gives approximately:
[tex]$$
\text{moles} \approx 0.9295 \text{ mol}
$$[/tex]
Step 2: Calculate the Molarity
The volume of the solution is given as [tex]$1.59 \text{ L}$[/tex]. Molarity (mol/L) is calculated by:
[tex]$$
\text{molarity} = \frac{\text{moles}}{\text{volume in liters}} = \frac{0.9295 \text{ mol}}{1.59 \text{ L}}
$$[/tex]
Which gives approximately:
[tex]$$
\text{molarity} \approx 0.5846 \text{ M}
$$[/tex]
Final Answer:
The molarity of the solution is approximately [tex]$0.5846 \frac{\text{mol}}{\text{L}}$[/tex].
Step 1: Calculate the Moles
Given:
- Mass of [tex]$\mathrm{LiCl}$[/tex]: [tex]$39.4 \text{ g}$[/tex]
- Molar mass of [tex]$\mathrm{LiCl}$[/tex]: [tex]$42.39 \text{ g/mol}$[/tex]
The number of moles is calculated using the formula:
[tex]$$
\text{moles} = \frac{\text{mass}}{\text{molar mass}} = \frac{39.4 \text{ g}}{42.39 \text{ g/mol}}
$$[/tex]
This gives approximately:
[tex]$$
\text{moles} \approx 0.9295 \text{ mol}
$$[/tex]
Step 2: Calculate the Molarity
The volume of the solution is given as [tex]$1.59 \text{ L}$[/tex]. Molarity (mol/L) is calculated by:
[tex]$$
\text{molarity} = \frac{\text{moles}}{\text{volume in liters}} = \frac{0.9295 \text{ mol}}{1.59 \text{ L}}
$$[/tex]
Which gives approximately:
[tex]$$
\text{molarity} \approx 0.5846 \text{ M}
$$[/tex]
Final Answer:
The molarity of the solution is approximately [tex]$0.5846 \frac{\text{mol}}{\text{L}}$[/tex].
