Answer :
Final answer:
The pressure drop allowed by the codes for a natural gas piping system with a supply pressure of 5 psi is 0.5 psi.
Explanation:
The pressure drop allowed by the codes for a natural gas piping system can be calculated using the formula: pressure drop = (flow rate * resistance). Assuming the resistance is constant, we can calculate the pressure drop using the given information. The original flow rate was 200 L/min and the pressure at the entrance of the water main was 5.00 × 10^5 N/m². The current flow rate is 8.00 L/min. Using the formula, we can calculate the new pressure supplied to the house:
Pressure drop = (200 - 8) * resistance
5 × 10^5 N/m² - Pressure drop = Pressure supplied to the house
Once we calculate the pressure drop, we can subtract it from the entrance pressure to find the new pressure supplied to the house. The maximum pressure drop allowed by the codes for a natural gas piping system with a supply pressure of 5 psi is 0.5 psi. Therefore, the answer is d) 3 psi.
