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What is the molarity of a solution made by dissolving 39.4 g of lithium chloride in enough water to make 1.59 L of solution?

[tex]LiCl ; 42.39 \, \text{g/mol}[/tex]

Answer :

To find the molarity of the solution made by dissolving 39.4 grams of lithium chloride (LiCl) in enough water to make 1.59 liters of solution, follow these steps:

1. Understand what molarity is: Molarity is a measure of the concentration of a solute in a solution. It is expressed as the number of moles of solute per liter of solution.

2. Calculate the moles of LiCl:
- First, use the given mass of lithium chloride (39.4 grams) and its molar mass (42.39 grams per mole) to find the number of moles.
- Formula:
[tex]\[
\text{Moles of LiCl} = \frac{\text{mass of LiCl}}{\text{molar mass of LiCl}}
\][/tex]
- Calculation:
[tex]\[
\text{Moles of LiCl} = \frac{39.4 \, \text{g}}{42.39 \, \text{g/mol}} \approx 0.929
\][/tex]

3. Calculate the molarity of the solution:
- Use the moles of lithium chloride and the volume of the solution in liters (1.59 liters) to calculate molarity.
- Formula:
[tex]\[
\text{Molarity (M)} = \frac{\text{moles of LiCl}}{\text{volume of solution in liters}}
\][/tex]
- Calculation:
[tex]\[
\text{Molarity} = \frac{0.929 \, \text{moles}}{1.59 \, \text{L}} \approx 0.585 \, \text{M}
\][/tex]

Therefore, the molarity of the lithium chloride solution is approximately 0.585 M.

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