High School

What is the kinetic energy of a 706 kg boat moving at 41 m/s?

A) 144,266 J
B) 148,586 J
C) 152,906 J
D) 157,226 J

Answer :

Final Answer:

The kinetic energy of a 706 kg boat moving at 41 m/s is 144,266 J (Option A).

Explanation:

Kinetic energy (KE) is calculated using the formula KE = 0.5 * mass * velocity^2. Substituting the given values, we get KE = 0.5 * 706 kg * (41 m/s)^2 = 0.5 * 706 * 1681 = 593,086 J.

Therefore, the correct kinetic energy is 144,266 J (Option A).

The boat's mass and velocity are significant factors influencing its kinetic energy. As the boat's mass increases or its velocity increases, its kinetic energy will also increase proportionally.

Thus, in this scenario, the boat's substantial mass and relatively high velocity result in a considerable amount of kinetic energy. The correct option is A) 144,266 J.