Answer :
The current in a circuit with a 12 V battery and three resistors of 4 ohms, 6 ohms, and 8 ohms connected in series is calculated to be 0.67 amperes (A) using Ohm's Law.
To calculate the current in a circuit with a 12 V battery and three resistors of 4 ohms, 6 ohms, and 8 ohms connected in series, we use Ohm's Law, which states I = V / R, where I is the current, V is the voltage, and R is the total resistance.
First, we find the total resistance in the circuit by adding the resistance values of all the resistors in series:
- Rtotal = R1 + R2 + R3 = 4 "+" 6 "+" 8 = 18 ohms
Next, we apply Ohm's Law to find the current:
- I = V / Rtotal = 12 V / 18 "+" = 0.67 A
Therefore, the current flowing through the circuit is 0.67 amperes (A).
