Answer :
Final answer:
To neutralize 2L of 2M HF, a concentration of 1M NaOH is required.
Explanation:
To find the concentration of NaOH needed to neutralize 2L of 2M HF, we can use the formula C₂V₁ = C₂V₂. In this case, C₁ represents the concentration of NaOH, V₁ represents the volume of NaOH, C₂ represents the concentration of HF, and V₂ represents the volume of HF.
First, rearrange the formula to solve for C₁:
C₁ = (C₂V₂) / V₁
Substituting the given values, we have:
C₁ = (2M * 2L) / 4L = 1M
Therefore, the concentration of 4L NaOH needed to neutralize 2L of 2M HF is 1M.
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