High School

Weights of eggs: 95% confidence; [tex]n=59[/tex], [tex]\bar{x}=1.79[/tex] oz, [tex]s=0.48[/tex] oz.

Find the margin of error.

A. 0.16 oz
B. 0.36 oz
C. 0.13 oz
D. 0.02 oz

Answer :

Therefore, the correct answer is a) 0.16 oz.

Explanation: To find the margin of error, we use the formula: Margin of Error = z * (a/sqrt(n)), where z is the z-score for the desired confidence level (in this case, 95% corresponds to a z-score of 1.96), a is the standard deviation, and n is the sample size. Plugging in the values, we get a Margin of Error = 1.96 * (0.48/sqrt(59)) = 0.16 oz.

Therefore, the correct answer is a) 0.16 oz.

To learn more about the mean and standard deviation visit:

brainly.com/question/475676

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