If 97.5 mL of a liquid weighed 225.9 g, what would be the density in g/mL? Round your answer to the correct number of significant figures and include the unit.

To find the density of the liquid in [tex]$ g/mL $[/tex], we can follow these steps:

1. Identify the given values:
- Volume of the liquid, [tex]$ V = 97.5 $[/tex] mL
- Mass of the liquid, [tex]$ m = 225.9 $[/tex] g

2. Understand the formula for density:
[tex]\[
\text{Density} = \frac{\text{Mass}}{\text{Volume}}
\][/tex]

3. Plug in the given values into the formula:
[tex]\[
\text{Density} = \frac{225.9 \, \text{g}}{97.5 \, \text{mL}}
\][/tex]

4. Perform the division:
[tex]\[
\text{Density} \approx 2.317 \, \text{g/mL}
\][/tex]

5. Determine the correct number of significant figures:
Both the volume (97.5 mL) and the mass (225.9 g) have 3 significant figures. Therefore, the result should also be rounded to 3 significant figures.

6. Round the density to 3 significant figures:
[tex]\[
\text{Density} = 2.32 \, \text{g/mL}
\][/tex]

Therefore, the density of the liquid is [tex]$ 2.32 \, \text{g/mL} $[/tex], rounded to 3 significant figures.