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------------------------------------------------ Water flows into a tank with dimensions 200 m × 150 m through a rectangular pipe measuring 1.5 m × 1.25 m at a speed of 20 km/h. In what time (in minutes) will the water rise by 2 meters?

Volume required in the tank = [tex](200 \times 150 \times 2) \, \text{m}^3 = 60000 \, \text{m}^3[/tex].

To determine the time it will take for the water to rise by 2 meters in the tank, we first need to calculate the volume of water required and the rate at which water is flowing into the tank.

Calculate the Volume of Water Needed:
The dimensions of the tank are 200 meters by 150 meters, and the water needs to rise by 2 meters.
[tex]\text{Volume required} = 200 \times 150 \times 2 = 60,000 \text{ m}^3[/tex]
Calculate the Flow Rate of the Pipe:
The dimensions of the rectangular pipe are 1.5 meters by 1.25 meters, and water flows through it at a speed of 20 kilometers per hour.
First, we convert the speed of water from kilometers per hour to meters per hour:
[tex]20 \text{ km/h} = 20,000 \text{ m/h}[/tex]
The cross-sectional area of the pipe is calculated as:
[tex]\text{Area of the pipe} = 1.5 \times 1.25 = 1.875 \text{ m}^2[/tex]
The volume of water flowing through the pipe in one hour is:
[tex]\text{Flow rate} = 1.875 \times 20,000 = 37,500 \text{ m}^3/\text{hour}[/tex]
Calculate the Time Required:
Now, we find the time required to fill the tank to achieve the required volume:
[tex]\text{Time (in hours)} = \frac{\text{Volume required}}{\text{Flow rate}} = \frac{60,000}{37,500} = 1.6 \text{ hours}[/tex]
To convert hours into minutes, multiply by 60:
[tex]1.6 \times 60 = 96 \text{ minutes}[/tex]

So, it will take 96 minutes for the water to rise by 2 meters in the tank.