Answer :
Sure! Let's solve these division problems step-by-step using the method of partial quotients.
### Exercise 1: Divide 92 by 4
1. Start with 92 and divide by 4.
2. We estimate how many times 4 fits into 92.
3. 4 fits into 92 exactly 23 times, since 4 × 23 = 92.
4. Subtract 92 from 92, resulting in a remainder of 0.
5. The quotient is 23 and the remainder is 0.
Result: 92 ÷ 4 = 23, R = 0
### Exercise 2: Divide 36 by 2
1. Start with 36 and divide by 2.
2. 2 fits into 36 exactly 18 times, because 2 × 18 = 36.
3. Subtract 36 from 36, leaving a remainder of 0.
4. The quotient is 18 with a remainder of 0.
Result: 36 ÷ 2 = 18, R = 0
### Exercise 3: Divide 75 by 5
1. Start with 75 and divide by 5.
2. 5 fits into 75 exactly 15 times, since 5 × 15 = 75.
3. Subtract 75 from 75, leaving a remainder of 0.
4. The quotient is 15 with a remainder of 0.
Result: 75 ÷ 5 = 15, R = 0
### Exercise 4: Divide 72 by 3
1. Start with 72 and divide by 3.
2. 3 fits into 72 exactly 24 times, as 3 × 24 = 72.
3. Subtract 72 from 72, leaving a remainder of 0.
4. The quotient is 24 with a remainder of 0.
Result: 72 ÷ 3 = 24, R = 0
### Exercise 7: Divide 91 by 7
1. Start with 91 and divide by 7.
2. 7 fits into 91 exactly 13 times, because 7 × 13 = 91.
3. Subtract 91 from 91, resulting in a remainder of 0.
4. The quotient is 13 with a remainder of 0.
Result: 91 ÷ 7 = 13, R = 0
### Exercise 8: Divide 99 by 3
1. Start with 99 and divide by 3.
2. 3 fits into 99 exactly 33 times, since 3 × 33 = 99.
3. Subtract 99 from 99, leaving a remainder of 0.
4. The quotient is 33 with a remainder of 0.
Result: 99 ÷ 3 = 33, R = 0
These are the solutions to the division exercises using partial quotients!
### Exercise 1: Divide 92 by 4
1. Start with 92 and divide by 4.
2. We estimate how many times 4 fits into 92.
3. 4 fits into 92 exactly 23 times, since 4 × 23 = 92.
4. Subtract 92 from 92, resulting in a remainder of 0.
5. The quotient is 23 and the remainder is 0.
Result: 92 ÷ 4 = 23, R = 0
### Exercise 2: Divide 36 by 2
1. Start with 36 and divide by 2.
2. 2 fits into 36 exactly 18 times, because 2 × 18 = 36.
3. Subtract 36 from 36, leaving a remainder of 0.
4. The quotient is 18 with a remainder of 0.
Result: 36 ÷ 2 = 18, R = 0
### Exercise 3: Divide 75 by 5
1. Start with 75 and divide by 5.
2. 5 fits into 75 exactly 15 times, since 5 × 15 = 75.
3. Subtract 75 from 75, leaving a remainder of 0.
4. The quotient is 15 with a remainder of 0.
Result: 75 ÷ 5 = 15, R = 0
### Exercise 4: Divide 72 by 3
1. Start with 72 and divide by 3.
2. 3 fits into 72 exactly 24 times, as 3 × 24 = 72.
3. Subtract 72 from 72, leaving a remainder of 0.
4. The quotient is 24 with a remainder of 0.
Result: 72 ÷ 3 = 24, R = 0
### Exercise 7: Divide 91 by 7
1. Start with 91 and divide by 7.
2. 7 fits into 91 exactly 13 times, because 7 × 13 = 91.
3. Subtract 91 from 91, resulting in a remainder of 0.
4. The quotient is 13 with a remainder of 0.
Result: 91 ÷ 7 = 13, R = 0
### Exercise 8: Divide 99 by 3
1. Start with 99 and divide by 3.
2. 3 fits into 99 exactly 33 times, since 3 × 33 = 99.
3. Subtract 99 from 99, leaving a remainder of 0.
4. The quotient is 33 with a remainder of 0.
Result: 99 ÷ 3 = 33, R = 0
These are the solutions to the division exercises using partial quotients!
