High School

Type the correct answer in the box. Use numerals instead of words. If necessary, use / for the fraction bar(s).

[tex]\[

\begin{array}{|c|c|c|c|c|c|}

\hline

\text{Viewer's Age Group} & \text{Excellent} & \text{Good} & \text{Average} & \text{Poor} & \text{Marginal Total} \\

\hline

16-25 & 52 & 42 & 12 & 7 & 113 \\

\hline

26-35 & 33 & 50 & 5 & 9 & 97 \\

\hline

36-45 & 25 & 17 & 22 & 12 & 76 \\

\hline

46-55 & & & 3 & 8 & 28 \\

\hline

56+ & 12 & 5 & 70 & 70 & 157 \\

\hline

\end{array}

\][/tex]

A movie producer conducted a survey after a preview screening of her new movie to find out how the film would be received by viewers from different age groups. The table shows the numbers of viewers in different age groups who rated the film excellent, good, average, and poor.

Out of the total respondents, the percentage of respondents from the 46-55 age group who rated the film excellent is [tex]$\square$[/tex] \%. Write your answer up to two decimal places.

Answer :

To find the percentage of respondents from the 46-55 age group who rated the film as excellent, we can follow these steps:

1. Identify the Total Number: From the table, the total number of respondents in the 46-55 age group is 28.

2. Identify the Number of Excellent Ratings: The table does not provide a number of respondents from the 46-55 age group who rated the film as excellent. In this case, the number is considered to be 0.

3. Calculate the Percentage: Using the information that 0 people rated the film as excellent, calculate the percentage:

[tex]\[
\text{Percentage} = \left( \frac{\text{Number of Excellent Ratings}}{\text{Total Respondents in 46-55 Age Group}} \right) \times 100
\][/tex]

So:

[tex]\[
\text{Percentage} = \left( \frac{0}{28} \right) \times 100 = 0\%
\][/tex]

Thus, the percentage of respondents from the 46-55 age group who rated the film excellent is [tex]\(0.00\%\)[/tex].