High School

Two water tanks are leaking. Tank A has leaked [tex]\frac{1}{16}[/tex] of a gallon in [tex]\frac{1}{12}[/tex] minute, and Tank B has leaked [tex]\frac{3}{80}[/tex] of a gallon in [tex]\frac{1}{30}[/tex] minute.

Which tank is leaking faster?

Answer :

Answer:

Tank B

Step-by-step explanation:

In gallons per minute, the leak rates are ...

Tank A: (1/16 gal)/(1/12 min) = 12/16 gal/min = 3/4 gal/min

Tank B: (3/80 gal)/(1/30 min) = 90/80 gal/min = 9/8 gal/min

Tank A leaks less than 1 gallon per minute, while Tank B leaks more than 1 gallon per minute.

Tank B is leaking faster.

Final answer:

By calculating the leakage rate or volume of water leaked per minute for both tanks, we find that Tank A is leaking faster than Tank B with a leakage rate of 0.75 gallons per minute compared to Tank B's rate of 0.375 gallons per minute.

Explanation:

To find out which tank is leaking faster, we need to determine the leakage rate of both tanks.

For Tank A, it leaked 1/16 of a gallon in 1/12 minute. To get the leakage rate per minute, we divide the volume of water leaked by the time it took for that volume to leak. So, the leakage rate of Tank A is (1/16) / (1/12) = 12/16 = 0.75 gallons per minute.

Similarly, for Tank B, it leaked 3/80 of a gallon in 1/30 minute. So, the leakage rate of Tank B would be (3/80) / (1/30) = 30/80 = 0.375 gallons per minute.

Therefore, Tank A is leaking faster than Tank B because its leakage rate is higher.

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