Two people stand facing each other at a roller skating rink and then push off each other.

If one skater has a mass of 44 kg and moves backward at 1.60 m/s, what is the velocity of the second skater if his mass is 67 kg?

Here we use the principle of conservation of momentum which states that p_1 + p_2 = 0 or p_1 = -p_2. The formula for momentum is p = mv, which means that m_1*v_1 = -m_2*v_2. Rearranging this equation to find v_2, we get -m_1*v_1/m_2 = v_2 (dividing both sides by -m_2.)

Now plugging in the numbers we get -44*1.60/67 = -1.05 m/s, which intuitively makes sense, since it takes more force to change the speed of, or accelerate, a heavier object (or, in this case, person.)

Two people stand facing each other at a roller skating rink and then push off each other. If one skater has a mass of 44 kg and moves backward at 1.60 m/s, what is the velocity of the second skater if his mass is 67 kg?

Answer :

Other Questions

Two people stand facing each other at a roller skating rink and then push off each other.

If one skater has a mass of 44 kg and moves backward at 1.60 m/s, what is the velocity of the second skater if his mass is 67 kg?