College

Two people of different masses sit on a seesaw. The mass of person 1, [tex]m_1[/tex], is 93 kg, and the mass of person 2, [tex]m_2[/tex], is 44 kg. The distance from the pivot for person 1, [tex]d_1[/tex], is 0.8 m, and for person 2, [tex]d_2[/tex], is 1.2 m. The mass of the board is negligible.

(a) What is the magnitude of the torque about the pivot due to the gravitational force on person 1?

[tex]|\tau_{a,1}| = [/tex] n · m

Answer :

Torque = Force * Distance

Force = Weight = m1*g = 93*9.81 = 912.33 N
Distance from the pivot to person 1, d1 = 0.8 m

Therefore,

Torque = 912.33*0.8 = 729.864 N.m

Other Questions