High School

Two objects are pulled across a frictionless surface as shown. Determine the acceleration of the objects for [tex]m_1 = 6.00 \, \text{kg}[/tex], [tex]m_2 = 4.00 \, \text{kg}[/tex], and [tex]f = 8.00 \, \text{N}[/tex].

A. 1.50 m/s²
B. 4.00 m/s²
C. 0.80 m/s²
D. 0.75 m/s²

Answer :

Final answer:

Option c, the acceleration of the objects pulled across a frictionless surface with masses 6.00 kg and 4.00 kg acted upon by an 8.00 N force is 0.80 m/s².

Explanation:

To determine the acceleration of two objects pulled across a frictionless surface, we use Newton's second law of motion, which states that the force equals mass times acceleration (F = ma). With the given masses of m1 = 6.00 kg and m2 = 4.00 kg, and a force of f = 8.00 N applied, the total mass involved in the motion is m1 + m2. Therefore, we can calculate the acceleration (a) by dividing the total force by the total mass.

Using the formula:

a = F(m1 + m2)

a = (8.00 N) (6.00 kg + 4.00 kg)

a = (8.00 N) (10.00 kg) = 0.80 m/s²

Therefore, the acceleration of the objects is 0.80 m/s².