High School

Two blocks of ice collide elastically. A 10.0 kg block of ice is sliding due east at 8.00 m/s when it collides with a 6.00 kg block of ice that is sliding in the same direction at 4.00 m/s. What is the final velocity of the 10.0 kg block of ice after the collision?

A. 4.00 m/s
B. 5.00 m/s
C. 6.00 m/s
D. 7.00 m/s

Answer :

Final answer:

The final velocity of the 10.0 kg block of ice after the elastic collision is 5.00 m/s according to the principle of conservation of momentum.

Explanation:

This is a Physics problem dealing with elastic collisions in one dimension. The main principle that will be used to solve this is the conservation of momentum. The equation for conservation of momentum is m1v1 + m2v2 = m1v1' + m2v2', where the primes indicate the values after the collision. In this situation, we have to solve for v1', the final velocity of the 10.0 kg block of ice.

Filling the data we have, 10kg * 8 m/s + 6 kg * 4 m/s = 10kg * v1' + 6 kg* (-4 m/s). Solving this equation, we find that the final velocity v1' of the 10.0 kg block of ice is 5.00 m/s.

So the correct option is Option 2: 5.00 m/s.

Learn more about Elastic Collisions here:

https://brainly.com/question/33268757

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