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------------------------------------------------ To what note is the highest string on a violin tuned?

How long is the vibrating part of the string on a full-size violin?

Answer :

The highest string on a violin is tuned to E^5. The vibrating part of the string on a full-size violin is approximately 32.7 cm long.

The highest string on a violin is tuned to E^5. This means it produces the note E in the fifth octave of the musical scale. Each octave corresponds to a doubling of frequency. The fifth octave of the E note has a frequency of approximately 659.255 Hz.

To calculate the length of the vibrating part of the string on a full-size violin, we can use the formula for the fundamental frequency of a vibrating string:

f = (1/2L)√(T/μ)

Where:

f = frequency of the string,

L = length of the vibrating part of the string,

T = tension in the string, and

μ = linear density of the string.

For a full-size violin, the tension is typically around 60 N, and the linear density is approximately 0.02 kg/m. Substituting these values into the formula and rearranging to solve for L, we get:

L = (1/2) × (T / (f^2 × μ))

L = (1/2) × (60 / ((659.255)^2 × 0.02))

L ≈ 0.327 m

Converting meters to centimeters, the length of the vibrating part of the string is approximately 32.7 cm. Therefore, the vibrating part of the highest string on a full-size violin is about 32.7 cm long.