Answer :
Final answer:
The acceleration of the leftmost car is approximately 6.93 m/s².
Explanation:
The acceleration of the leftmost car can be determined by using Newton's Second Law of Motion, which states that the force applied to an object is equal to its mass multiplied by its acceleration. In this case, the force applied to the rightmost car is 208 N, and the mass of each car is 10 kg. Since the cars are connected by a rod, they will move together with the same acceleration.
To find the acceleration, we need to calculate the total mass of the system. Since there are three cars, each with a mass of 10 kg, the total mass is 3 x 10 kg = 30 kg. Now we can use Newton's Second Law to find the acceleration:
Force = Mass x Acceleration
208 N = 30 kg x Acceleration
Acceleration = 208 N / 30 kg
Acceleration ≈ 6.93 m/s²
Therefore, the acceleration of the leftmost car is approximately 6.93 m/s².
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