Three pipes in a school building are

leaking. After 30 minutes, pipe A has leaked 3/4 gallon of water. After 45 minutes, pipe B has leaked 1 1/4 gallons of water. After 20 minutes, pipe C has leaked 1/2 gallon of water.

Which sentence is true?

A. Pipe A is leaking at the fastest rate

B. Pipe C is leaking at the slowest rate.

C. Pipe A and C are leaking at the same rate.

D. Pipes A and B are leaking at a faster rate than Pipe C.

To determine which pipe is leaking at the fastest rate, we need to calculate the rate of leakage for each pipe. We can do this by dividing the amount of water leaked by the time it took to leak. For Pipe A, the rate of leakage is 3/4 gallon divided by 30 minutes, which is 1/10 gallon per minute. For Pipe B, the rate of leakage is 1 1/4 gallons divided by 45 minutes, which is 1/36 gallon per minute. And for Pipe C, the rate of leakage is 1/2 gallon divided by 20 minutes, which is 1/40 gallon per minute.

Comparing the rates, we can see that Pipe A has the highest rate of leakage, so the sentence 'Pipe A is leaking at the fastest rate' is true. Therefore, the correct answer is A.

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Rxflex Rxflex · Answer 2 · 2024-08-05T02:09:49-04:00

Answer: Option C

Step-by-step explanation: To compare the rates at which the pipes are leaking, we can find the amount of water each pipe leaks per minute.

For Pipe A:

3/4 gallon ÷ 30 minutes = 1/40 gallon per minute

For Pipe B:

1 1/4 gallon ÷ 45 minutes = 5/36 gallon per minute

For Pipe C:

1/2 gallon ÷ 20 minutes = 1/40 gallon per minute

Therefore, Pipes A and C are leaking at the same rate, which means option C is true. Option A and D are false, as Pipe B has the fastest leak rate. Option B is false, as both Pipe A and Pipe C are leaking at the same rate.