Answer :
To draw the impedance diagram of the system in per unit, convert the given impedance values to per unit values using the formula: Z_perunit = (Z / S_base) * (V_base^2 / V^2).
What is the formula for calculating the apparent power in a three-phase system?
To draw the impedance diagram of the system in per unit, we need to convert the given impedance values to per unit values. Given that S_base = 100 MVA and V_base = 20 kV for the generator, we can calculate the per unit impedance values as follows:
Generator:
Zg = 9% of 60 MVA = 0.09 * 60 = 5.4 MVA
Zg_perunit = (Zg / S_base) * (V_base^2 / Vg^2) = (5.4 / 100) * (20^2 / 20^2) = 0.0027 pu
Transformer T1:
Zt1 = 10% of 50 MVA = 0.1 * 50 = 5 MVA
Zt1_perunit = (Zt1 / S_base) * (V_base^2 / Vt1^2) = (5 / 100) * (20^2 / 200^2) = 0.0005 pu
Transformer T2:
Zt2 = 12% of 80 MVA = 0.12 * 80 = 9.6 MVA
Zt2_perunit = (Zt2 / S_base) * (V_base^2 / Vt2^2) = (9.6 / 100) * (20^2 / 20^2) = 0.0048 pu
Load:
Zload = 120 + j200 Ω
Zload_perunit = (Zload / S_base) * (V_base^2 / S_base) = (120 + j200) / (100 * (20^2)) = 0.06 + j0.1 pu
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