Answer :
In a circuit with three identical resistors connected in series to a 12 V battery, each resistor has a resistance of 12 Ω. for hence, option D) 12 Ω is the correct answer.
In this circuit, three identical resistors are connected in series to a 12 V battery, resulting in a total current of 1 A flowing through the circuit. To calculate the resistance of each resistor, we can use Ohm's Law: Resistance (R) = Voltage (V) / Current (I). Since the total current is 1 A and the voltage is 12 V, the resistance of each resistor would be 12 Ω. The total resistance of three identical resistors in series is 12 Ω, and since they are identical, each resistor has a resistance of 4 Ω.
The question pertains to a physics concept dealing with electric circuits, particularly ohmic resistors connected in series. Given the conditions of the problem, with a total voltage of 12 V and a current of 1 A flowing through the circuit, the combined resistance of the three identical resistors can be determined using Ohm's law, which states V = IR, where V is voltage, I is current, and R is resistance. To find the total resistance R, we rearrange the formula to R = V / I. Substituting the given values, we get R = 12 V / 1 A, which equals 12 Ω. Because the resistors are identical and connected in series, the total resistance is the sum of each resistor's resistance. Therefore, each resistor has a resistance of 4 Ω since 12 Ω divided by 3 equals 4 Ω. for hence, option D) 12 Ω is the correct answer.
