Answer :
Final answer:
The original number of blue counters in the box was 162. This was determined by setting up an equation based on the given ratios and the fact that 45 blue counters were removed.
Explanation:
We are given a scenario in which there are three times as many blue counters as yellow counters in a box. After removing 45 blue counters, there are now 63 more blue counters than yellow counters. To find the original number of blue counters, let's define the variables:
Let x be the number of yellow counters.
The number of blue counters would then be 3x.
After removing 45 blue counters, the equation representing the current situation is:
3x - 45 = x + 63
Solving for x:
3x - x = 63 + 45
2x = 108
x = 54
Now we know there were 54 yellow counters initially. Since there were three times as many blue counters:
Number of blue counters = 3 × 54 = 162
There were 162 blue counters in the box at the start.
The number of blue counters that were in the box at the start is; 162 blue counters
How to solve Algebra Word problems?
Let the number of yellow counters be x.
Thus, since there are 3 times as many blue counters as yellow counters in a box, then;
Number of blue counters = 3x
45 blue counters are removed from the box. Thus, we now have;
(3x - 45)
There are now 63 more blue counters than yellow counters in the box. Thus;
(3x - 45) - x = 63
2x - 45 = 63
2x = 63 + 45
2x = 108
x = 108/2
x = 54
Thus, number of blue counters at the beginning = 3 * 54 = 162
Read more about Algebra Word Problems at; https://brainly.com/question/13818690
#SPJ1
