In one of the pans of the beam balance, masses of 3 kg, 900 g, 90 g, and 5 g are placed. What amount of mass should be placed on the other side of the beam balance to make it balanced?

In order to balance the beam, an equal amount of mass must be placed on the other side. To determine the mass needed, we need to add up the masses on one side and then subtract that total from the total mass on the other side. The masses on one side are 3 kg, 900 g, 90 g, and 5 g, which can be converted to a total of 3000 g + 900 g + 90 g + 5 g = 3995 g. Therefore, an equal amount of mass, 3995 g, should be placed on the other side of the beam balance.

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purpleSnowflake79 purpleSnowflake79 · Answer 2 · 2023-08-23T15:11:35-04:00

Final answer:

To make the beam balance balanced, a mass of 3995 grams should be placed on the other side.

Explanation:

To make the beam balance balanced, the mass on one side needs to be equal to the mass on the other side. In this case, the masses on one side are 3 kg, 900 g, 90 g, and 5 g. We need to find the sum of these masses in order to determine the amount of mass that should be placed on the other side.

Sum of masses on one side:

3 kg = 3000 g
900 g
90 g
5 g

Sum = 3000 g + 900 g + 90 g + 5 g = 3995 g

To balance the beam, we need to place a mass of 3995 grams on the other side of the beam balance.

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