High School

There are 10 red counters and [tex]x[/tex] blue counters in a bag. Two counters are removed from the bag. The probability that both counters are blue is [tex]\frac{1}{8}[/tex]. How many counters are there altogether?

Answer :

Final answer:

To find the total number of counters in the bag, we set up an equation using the given probabilities and solve for x. The solution is x = 24 and the total number of counters is 34.

Explanation:

Let the number of blue counters be x.

Since there are 10 red counters and x blue counters in the bag, the total number of counters is 10 + x.

The probability that the first counter drawn is blue is x/(10 + x). Since one blue counter has been removed, there are now x - 1 blue counters left. Therefore, the probability that the second counter drawn is blue is (x - 1)/(9 + x).

According to the problem, the probability that both counters drawn are blue is 1/8. So we can write the equation: x/(10 + x) * (x - 1)/(9 + x) = 1/8.

Simplifying the equation and solving for x, we find that x = 24.

Therefore, the total number of counters is 10 + 24 = 34.

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