Answer :
The object was initially dropped from a height of about 287.6 meters.
We can change the acceleration due to gravity on the moon to g = 1.57 [tex]m/s^2[/tex] and use this value in the formula:
h = [tex]900 m^2/s^2[/tex] / (2 × 1.57 m/s^2)
h ≈ 287.6 m
what is velocity?
The pace at which an object's position changes in relation to a frame of reference and time is what is meant by velocity. Although it may appear sophisticated, velocity is just the act of moving quickly in one direction. Since it is a vector quantity, the definition of velocity requires both magnitude (speed) and direction. Its SI equivalent is the meter per second (ms-1). A body is considered to be accelerating if its velocity changes, either in magnitude or direction.
from the question:
The starting height from which the object was dropped can be determined using the formula for the velocity of a free-falling object. When an object strikes a surface at 30 m/s, we can write:
30 m/s = √(2gh)
Squaring both sides gives:
[tex]900 m^2/s^2[/tex] = 2gh
Solving for h:
h = [tex]900 m^2/s^2[/tex]/ (2g)
We can change the acceleration due to gravity on the moon to g = 1.57 [tex]m/s^2[/tex] and use this value in the formula:
h = [tex]900 m^2/s^2[/tex] / (2 × 1.57 m/s^2)
h ≈ 287.6 m
As a result, the object was dropped from a height of roughly 287.6 meters.
Learn more about velocity here
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