High School

Dear beloved readers, welcome to our website! We hope your visit here brings you valuable insights and meaningful inspiration. Thank you for taking the time to stop by and explore the content we've prepared for you.
------------------------------------------------ The temperature at 6:00 AM is twenty degrees Celsius. By 6:00 PM, the temperature is negative thirty-three degrees Celsius. How much did the temperature decrease from 6:00 AM to 6:00 PM?

A. 53 degrees Celsius
B. 13 degrees Celsius
C. 53 degrees Fahrenheit
D. 13 degrees Fahrenheit

Answer :

Final answer:

The temperature decreased from 20 degrees Celsius at 6:00 AM to -33 degrees Celsius at 6:00 PM, for a total change of 53 degrees Celsius. The correct answer is a) 53 degrees Celsius.

Explanation:

To solve this question, we need to subtract the final temperature from the initial temperature. In this case, the initial temperature at 6:00 AM is twenty degrees Celsius and the final temperature at 6:00 PM is negative thirty-three degrees Celsius.

When you subtract -33 degrees Celsius (the final temperature) from 20 degrees Celsius (the initial temperature), the calculation becomes this: 20 - (-33). Subtracting a negative number is the same as adding its absolute value. So, the temperature difference is 20 + 33 or 53 degrees Celsius.

Therefore, the temperature decreased by 53 degrees Celsius from 6:00 AM to 6:00 PM. The correct answer to your question is option a) 53 degrees Celsius.

Learn more about Temperature Change here:

https://brainly.com/question/32089365

#SPJ11