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------------------------------------------------ The temperature at 6:00 AM is twenty degrees Celsius. By 6:00 PM, the temperature is negative thirty-three degrees Celsius. How much did the temperature decrease from 6:00 AM to 6:00 PM?

A. 53 degrees Celsius
B. 13 degrees Celsius
C. 53 degrees Fahrenheit
D. 13 degrees Fahrenheit

The temperature decreased from 20 degrees Celsius at 6:00 AM to -33 degrees Celsius at 6:00 PM, for a total change of 53 degrees Celsius. The correct answer is a) 53 degrees Celsius.

Explanation:

To solve this question, we need to subtract the final temperature from the initial temperature. In this case, the initial temperature at 6:00 AM is twenty degrees Celsius and the final temperature at 6:00 PM is negative thirty-three degrees Celsius.

When you subtract -33 degrees Celsius (the final temperature) from 20 degrees Celsius (the initial temperature), the calculation becomes this: 20 - (-33). Subtracting a negative number is the same as adding its absolute value. So, the temperature difference is 20 + 33 or 53 degrees Celsius.

Therefore, the temperature decreased by 53 degrees Celsius from 6:00 AM to 6:00 PM. The correct answer to your question is option a) 53 degrees Celsius.

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