Answer :
Because the string of a violin A vibrates 12 times in 4 seconds and the string of a violin B vibrates 18 times in 6 seconds, their frequencies are equal; that is, the string of a violin A and the string of a violin B have the same frequency of 3 Hz.
What is the calculation of the frequency of the violin?
The frequency of a string = number of complete cycles of vibration per unit time, and the calculation is given below,
For string A, the frequency is,
frequency = number of vibrations / time frequency
frequency = 12 vibrations / 4 sec= 3 Hz
For string B, the frequency is,
frequency = number of vibrations / time frequency
frequency = 18 vibrations / 6 sec = 3 Hz
Hence, because the string of a violin A vibrates 12 times in 4 seconds and the string of a violin B vibrates 18 times in 6 seconds, their frequencies are equal; that is, the string of a violin A and the string of a violin B have the same frequency of 3 Hz.
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