Answer :
Final answer:
The amount of heat energy required to raise the temperature of 10kg of lead by 15°C, given that the specific heat capacity of lead is 128 J/kg°C, is calculated using the equation q = mcΔT. The answer, in this case, is 19200 Joules.
Explanation:
The question is asking about the heat energy required to raise the temperature of a certain mass of lead. The concept involves understanding specific heat capacity, which is an intensive property of matter, meaning it depends only on the kind of substance and nothing else. The specific heat capacity of lead is given as 128 J/kg°C.
To find out the heat energy needed, you use the formula q = mcΔT, where 'q' is the heat energy, 'm' is the mass of the substance, 'c' is the specific heat capacity and 'ΔT' is the change in temperature. In this case, m = 10 kg, c = 128 J/kg°C, and ΔT = 15°C.
Applying the values into the equation: q = 10 kg * 128 J/kg°C * 15°C gives us the heat energy as 19200 J. Therefore, 19200 Joules of heat energy are required to raise the temperature of 10 kg of lead by 15°C.
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