Middle School

23 grams of sodium reacted with 35.5 grams of chlorine. Calculate the mass of the sodium chloride compound formed.

Answer :

Molar Masses:


MM of Na+ = 23 g / mol

MM of Cl- = 35.5 g / mol


Initially we must calculate the number of moles of each participant of the reaction, ie, sodium Na + and chlorine Cl-:

→ Number of moles of Na +


[tex]n = \frac{m}{MM} [/tex]
[tex]n = \frac{23}{23} [/tex]
n = 1 mol


→ Number of mols of Cl-


[tex]n = \frac{m}{MM} [/tex]
[tex]n = \frac{35.5}{35.5} [/tex]
n = 1 mol


Reaction:


Na + + Cl- -----------> NaCl


1 mole Na + ------------------ 1 mole NaCl

1 mole of Na + -------------- y

y = 1 mol of NaCl are produced


NaCl Molar Mass = 23 + 35.5 = 58.5 g / mol


1 mole of NaCl ---------------- 58.5 g

1 mol ----------------------- m


m = 58.5 grams of NaCl

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