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The solution in beaker A is 20% glucose, and the solution in beaker B is 40% glucose. If you connected the beakers with a tube that was permeable to water but impermeable to glucose, which way would water move?

A. From beaker A to beaker B
B. From beaker B to beaker A
C. Water would not move

Answer :

Let's solve the given question step-by-step to understand which way the water will move between the solutions in beaker A and beaker B.

Firstly, let's recall the principle of osmosis:
- Osmosis is the movement of water molecules across a semi-permeable membrane from an area of lower solute concentration to an area of higher solute concentration.

Given that:
- Beaker A contains a solution that is 20% glucose.
- Beaker B contains a solution that is 40% glucose.
- The tube connecting the beakers is permeable to water but not to glucose.

In Beaker A:
- There is 20% glucose, which means 80% of the solution is water.

In Beaker B:
- There is 40% glucose, which means 60% of the solution is water.

Now, we compare the concentration of water in the two beakers:
- Beaker A has a higher concentration of water (80%).
- Beaker B has a lower concentration of water (60%).

According to the principle of osmosis, water will move from an area of higher water concentration to an area of lower water concentration. Since Beaker A has a higher concentration of water than Beaker B, water will move from Beaker A to Beaker B.

So, the correct answer is: From Beaker A to Beaker B.

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