Answer :
Final answer:
To find the number of oxygen atoms in 6.00 g of sodium dichromate, we first calculate the number of moles of sodium dichromate and then use the Avogadro's number and the chemical formula to determine the number of oxygen atoms.
Explanation:
In order to determine the number of oxygen atoms in 6.00 g of sodium dichromate, we need to first find the number of moles of sodium dichromate. The molar mass of sodium dichromate (Na2Cr2O7) is 262 g/mol. So, we can use the formula:
Moles = Mass / Molar mass
Therefore, Moles of sodium dichromate = 6.00 g / 262 g/mol = 0.0229 mol
Next, we can use the chemical formula to determine the number of oxygen atoms present. As there are 7 oxygen atoms in one molecule of sodium dichromate, we can multiply the number of moles by the Avogadro's number (6.022 x 10^23 molecules/mol) and then multiply it by the number of oxygen atoms in one molecule:
Number of oxygen atoms = Moles of sodium dichromate * Avogadro's number * 7
Number of oxygen atoms = 0.0229 mol * (6.022 x 10^23 molecules/mol) * 7 = 9.75 x 10^22 oxygen atoms
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Final answer:
To determine the number of oxygen atoms in 6.00 g of Na₂Cr₂O7, you need to convert the mass to moles and then use the mole ratio to find the number of oxygen atoms.
Explanation:
To determine the number of oxygen atoms in 6.00 g of sodium dichromate (Na₂Cr₂O7), we need to convert the mass of the compound to moles and then use the mole ratio to find the number of oxygen atoms.
Step 1: Calculate the molar mass of Na₂Cr₂O7:
2(22.99 g/mol) + 2(52.00 g/mol) + 7(16.00 g/mol) = 262.00 g/mol
Step 2: Convert grams of Na₂Cr₂O7 to moles:
6.00 g / 262.00 g/mol = 0.0229 mol
Step 3: Use the mole ratio to find the number of oxygen atoms:
1 mol of Na₂Cr₂O7 contains 7 moles of oxygen atoms, so
0.0229 mol Na₂Cr₂O7 x 7 mol O = 0.1603 mol O
Therefore, there are approximately 0.1603 moles or 9.676 × 10^22 oxygen atoms in 6.00 g of sodium dichromate.
