Answer :
Let the first integer be [tex]$x$[/tex] and the second integer be expressed as [tex]$3x+4$[/tex] (since one number is four more than three times the other). Their product is given by
[tex]$$
x(3x+4)=112.
$$[/tex]
Expanding the left side gives
[tex]$$
3x^2+4x=112.
$$[/tex]
This equation matches option A:
[tex]$$
3x^2+4x=112.
$$[/tex]
Thus, the equation that can be used to find one of the numbers is option A.
[tex]$$
x(3x+4)=112.
$$[/tex]
Expanding the left side gives
[tex]$$
3x^2+4x=112.
$$[/tex]
This equation matches option A:
[tex]$$
3x^2+4x=112.
$$[/tex]
Thus, the equation that can be used to find one of the numbers is option A.
