High School

The product of two consecutive negative integers is 600. What is the value of the lesser integer?

A. -60
B. -30
C. -25
D. -15

Answer :

The value of the lesser integer is -25. Let's assume the two consecutive negative integers are x and (x+1). According to the given information, the product of these two integers is 600.

We can set up the equation as follows:

x * (x+1) = 600

Expanding the equation:

x^2 + x = 600

Rearranging the equation:

x^2 + x - 600 = 0

To solve this quadratic equation, we can factorize it or use the quadratic formula. In this case, let's factorize it:

(x - 25)(x + 24) = 0

From the factored form, we have two possible solutions:

x - 25 = 0 or x + 24 = 0

Solving these equations:

x = 25 or x = -24

Since we are looking for a negative integer, the lesser integer is -25.

Therefore, the value of the lesser integer is -25.

Learn more about integer here: brainly.com/question/490943

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QUESTION:

The product of two consecutive negative integers is 600. What is the value of the lesser integer?

A. –60

B. –30

C. –25

D. –15