The numbers 120 and 126, written as a product of their prime factors, are:

120 = [tex]2^3 \times 3 \times 5[/tex]
126 = [tex]2 \times 3^2 \times 7[/tex]

Find the smallest number divisible by both 120 and 126.

Prime Factorization is defined as any number that may be expressed as a product of prime numbers that has been said to be prime factorized. Any integer with exactly two factors 1 and the number itself. is said to be a prime number.

We need to write 126 and 120 as the product of their prime factors,

126 = 2×3×3×7

120 = 2×2×2×3×5

LCM = 2×2×2×3×3×5×7 = 2520.

Therefore, the smallest integer would be 2520 which is divisible by 126 and 120.

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The numbers 120 and 126, written as a product of their prime factors, are:120 = [tex]2^3 \times 3 \times 5[/tex] 126 = [tex]2 \times 3^2 \times 7[/tex] Find the smallest number divisible by both 120 and 126.

Answer :

What is Prime Factorization?

Other Questions

The numbers 120 and 126, written as a product of their prime factors, are:

120 = [tex]2^3 \times 3 \times 5[/tex]
126 = [tex]2 \times 3^2 \times 7[/tex]

Find the smallest number divisible by both 120 and 126.