High School

The number of grams of fiber eaten in one day for a sample of ten people are:

6, 9, 10, 14, 17, 21, 21, 28, 28, 116

(a) Find the mean and the median for these data.

(b) The value of 116 appears to be an obvious outlier. Compute the mean and the median for the nine numbers excluding 116.

Answer :

The mean of the data set is 27 and the median is 21. Excluding the outlier, the mean becomes 17.11 and the median remains 17.

To find the mean, sum up all the values and divide by the number of values. Here, the sum is

6 + 9 + 10 + 14 + 17 + 21 + 21 + 28 + 28 + 116 = 270

So the mean is 270 divided by 10, which is 27.

To find the median, first arrange the data in ascending order: 6 9 10 14 17 21 21 28 28 116. Since we have an odd number of values, the median is the middle value, which is 21.

Now, let's calculate the mean and median without the outlier value of 116. When we exclude 116, the sum becomes 270 - 116 = 154.

Since we have 9 values now, the mean is 154 divided by 9, which is 17.11.

The new data set without the outlier is 6 9 10 14 17 21 21 28 28, and the median is still 17.

Learn more about the topic of Central Tendency here:

https://brainly.com/question/12896875

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