Answer :
Final answer:
The closest object a young woman with normal distant vision and a 10% accommodation ability can see clearly is at approximately 18.18 centimeters from her eyes. This is calculated using the power of her eyes which increases from the normal 50.0 D for distant vision to 55.0 D for close vision.The correct option is (a)20/20.
Explanation:
The question addresses the concept of the power of the eye and how it relates to vision clarity at different distances. The eye can accommodate to focus on objects at varying distances by adjusting its power. In the context of the question, a young woman with normal distant vision has an ability to accommodate by a 10% increase in the power of her eyes. Considering the normal distant vision power is 50.0 diopters (D), a 10% increase would be an additional 5.0 D, making the total power 55.0 D when she is accommodating for close vision.
To identify the closest object she can see clearly, we can use the formula for power which is P = 1/f, where P is the power in diopters and f is the focal length in meters (m). If the power of the eye is 55.0 D for close vision, the focal length would be 1/55.0 m. Therefore, the closest distance at which she can see an object clearly would be the focal length when the eye is fully accommodated, which is approximately 0.01818 meters or 18.18 centimeters.
