A motorcycle has a constant speed of 25.0 m/s as it passes over the top of a hill whose radius of curvature is 126 m. The mass of the motorcycle and driver is 342 kg. Find the magnitude of the centripetal force.

The magnitude of the centripetal force acting on the motorcycle as it passes over the top of the hill is approximately 16851 N, calculated using the formula for centripetal force: F = mv²/r.

Explanation:

In this scenario, we need to calculate the magnitude of the centripetal force acting on the motorcycle. Centripetal force refers to the force that keeps a body moving in a circular path. It's always directed towards the centre of the path, and its magnitude is given by F = mv²/r, where m is the mass of the object, v is the speed, and r is the radius of the path.Here, we have the mass (m) as 342 kg, the speed (v) as 25.0 m/s, and the radius (r) as 126 m. Plugging these values into the formula:

F = (342 kg)(25.0 m/s)² / 126 m

After calculations, we get:

F ≈ 16850.89 N

So, the magnitude of the centripetal force acting on the motorcycle is approximately 16851 N.

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