Answer :
Final answer:
In this problem, we use a t-distribution to calculate the 95% confidence interval for the amount of trash generated per person per week. The interval is between 35.125 and 37.475 pounds. Around 95% of all confidence intervals from possible samples will contain the population mean, while about 5% will not.
Explanation:
For this problem, we should use a t-distribution because we don't know the standard deviation of the population. Since we are only given a sample standard deviation, t-distribution is most appropriate.
Now, let's calculate the confidence interval. The formula for a t-confidence interval is: x ± t * (s/√n). We have all these values; x (sample mean) = 36.3, t = t-critical for 95% confidence with 127 degrees of freedom (1.98 from the t-distribution table), s (sample standard deviation) = 6.7, and n (sample size) = 128.
The standard error 's/√n' equals about 0.593. Therefore, the confidence interval is 36.3 ± 1.98 * 0.593. That comes to between 35.125 and 37.475 pounds.
About 95% of the confidence intervals of all possible samples of size 128 will contain the true population mean number of pounds of trash generated per person per week. Therefore, about 5% will not contain the true population mean.
Learn more about t-distribution here:
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